Question

solve by elimination
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Answer 1

I don't no if this is the best way to solve this, but it worked. A better way to do this would involve creating a matrix and solving the determinants, but I haven't done that since college.

I solved this by subtracting the second equation from the first one. This wii eliminate the x term and leave an equation in terms of y and z, call it equation 4.
Then I added equation 1 and 3 together, again eliminating x, creating equation 5.

I then multiplied equation 4 by the number 3 and subtracted the new equation from equation 5. The result will eliminate the z term and solve for y. Then plug y into into equation 4 or 5 and solve for z. Then plug y and z into equation 1 2 or 3 and solve for x.

The answers for x, y and z might seem wrong, but if you double check them into all three equations you can verify their validity.

Answer 2

can u show your work

Answer 3

-2x+2y+3z =0--------(1)
-2x-y+z = -3---------(2)
2x+3y+3z=5-------(3)

Answer 4

add (1) +(3) u can get 5y+6z = 5-------(4)
(2) +(3) 2y +4z =2-------------(5)

Answer 5

2* (4) ------ 10y+12z=10 ------(6)
5*(5)------ 10y+20z =10 -------(7)
subtract (6) from (7)
8z =0
z= 0-----(8)
plug z=0 in (6)
you can get y= 1
plug z=0 and y=1 in (1)
you can get x=1
therefore
x=1, y=1 and z=0

Answer 6

z=0