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Physics 13 Online
OpenStudy (4everaddicted2anime):

If a 990 kg car is on the road and the Ff is 360 N, what is the normal force? I don't understand how to do this.

OpenStudy (anonymous):

Is it a horizontal road or an inclined road?

OpenStudy (4everaddicted2anime):

It doesn't say

OpenStudy (anonymous):

Than most probably horizontal you have along Y axis W+N=0 therfore N=m.g

OpenStudy (irishboy123):

your question doesn't make any sense are you given a coefficient of friction?

OpenStudy (anonymous):

It's very odd to include the frictional force in such a problem. Maybe it's just meant to throw you off by including extraneous information. We can find the normal force by drawing a free body diagram and analyzing the forces in the y-direction. |dw:1449178653674:dw| \[\huge \sum F_y = \text{N}-mg=0 \]This equation is equal to zero because it is not accelerating in the y-direction. Therefore:\[\huge \text{N}=mg\]

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