If a 990 kg car is on the road and the Ff is 360 N, what is the normal force? I don't understand how to do this.

Question

anonymous · Answer

Is it a horizontal road or an inclined road?

4everaddicted2anime · Answer

It doesn't say

anonymous · Answer

Than most probably horizontal you have along Y axis W+N=0 therfore N=m.g

irishboy123 · Answer

your question doesn't make any sense

are you given a coefficient of friction?

anonymous · Answer

It's very odd to include the frictional force in such a problem. Maybe it's just meant to throw you off by including extraneous information.

We can find the normal force by drawing a free body diagram and analyzing the forces in the y-direction.

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$$\huge \sum F_y = \text{N}-mg=0 $$This equation is equal to zero because it is not accelerating in the y-direction. Therefore:$$\huge \text{N}=mg$$