Calculate the enthalpy of the reaction
4B(s)+3O2(g)→2B2O3(s)
given the following pertinent information:
B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔH∘A=+2035 kJ
2B(s)+3H2(g)→B2H6(g), ΔH∘B=+36 kJ
H2(g)+12O2(g)→H2O(l), ΔH∘C=−285 kJ
H2O(l)→H2O(g), ΔH∘D=+44 kJ
Express your answer with the appropriate units.

Question

Calculate the enthalpy of the reaction
4B(s)+3O2(g)→2B2O3(s)
given the following pertinent information:
B2O3(s)+3H2O(g)→3O2(g)+B2H6(g),    ΔH∘A=+2035 kJ
2B(s)+3H2(g)→B2H6(g),                            ΔH∘B=+36 kJ
H2(g)+12O2(g)→H2O(l),                ΔH∘C=−285 kJ
H2O(l)→H2O(g),                                          ΔH∘D=+44 kJ
Express your answer with the appropriate units.

raffle_snaffle · Answer

Ive tried this problem 3 times and cant get rid of the 4th equation

raffle_snaffle · Answer

@abb0t

raffle_snaffle · Answer

@AloneS

raffle_snaffle · Answer

@sleepyjess

raffle_snaffle · Answer

@whpalmer4

abb0t · Answer

Use hess law.

abb0t · Answer

reverse 1 and 4

okdutchman7 · Answer

You have to determine the enthalpy of the reaction

raffle_snaffle · Answer

okay I will reverse one and four

raffle_snaffle · Answer

@abb0t by the way that isn't suppose to be a 12 suppose to be 1/2

raffle_snaffle · Answer

@okdutchman7 we need to use hess law

raffle_snaffle · Answer

how is reversing 4 going to help me?

raffle_snaffle · Answer

GOt it! And abbot you were not suppose to reverse 1 and 4.

abb0t · Answer

that thing is so hard to read. LOL.