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Prove that phi (7n) = 7phi (n) iff n is multiple of 7 Please, help. I stuck at the part phi (7n) = 7 phi (n), then n is multiple of 7
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phi (7n) = 7 phi (n), then n is multiple of 7 (proof by contradiction) suppose \(7\nmid n\), this means \(\gcd(n,7)=1\). since \(\phi\) is a multiplicative function, from the given equation it follows \[\phi(7n)=7\phi(n)\\~\\\phi(7)\phi(n)=7\phi(n)\\~\\6=7\] Contradiction, ending the proof.
@Loser66 do u got @ganeshie8 proof ?
I got him @ikram002p @ganeshie8 thank you so much
=)
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