Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

For right ∆ABC with right ∠C, prove each of the following. a. sin A < 1 b. cos A < 1

OpenStudy (danjs):

both sin and cos have maximum values at 1, what angles does that occure at for each

OpenStudy (anonymous):

um sorry im not to sure

OpenStudy (danjs):

OpenStudy (danjs):

since the radius is 1, all the hypotenuse are 1, so sin(a) = y and cos(a) = x each point on the circle (x , y) = (cos(a), sin(a))

OpenStudy (anonymous):

i have to write a proof

OpenStudy (danjs):

start by stating givens , i havent done a formal one in awhile

OpenStudy (danjs):

try and get through it before doing the formal proof maybe

OpenStudy (anonymous):

given sin A< 1

OpenStudy (danjs):

the given triangles are right the sum of the 3 angles in a triangle are 180, so the angles A and B add to 90

OpenStudy (danjs):

the range of values for cos(a) and sin(a), are from -1 to 1 cos(0) = 1 cos(90) = -1, for example

OpenStudy (anonymous):

ok

OpenStudy (danjs):

angles A + B + C = 180, and C is said to be 90, so A + B = 90

OpenStudy (anonymous):

ok

OpenStudy (danjs):

we are talking about a distance, lengths of the sides, forget about the negative part on the domain of sin and cos, so sin(a) < 1 cos(b) < 1

OpenStudy (anonymous):

ok

OpenStudy (danjs):

that restricts all the angles to the first quadrant on that circle, and not including 90, or 0

OpenStudy (danjs):

to prove those, say A+B=90 so angles A and B must both be some value between 0 and 90, not including 0 or 90

OpenStudy (anonymous):

ok thanks!!

OpenStudy (danjs):

then apply that to the definition of sin and cos sin(0) = 0 sin(90 = 1 sin has to be less than 1

OpenStudy (anonymous):

ok thanks

OpenStudy (danjs):

welcome, i think most of the ideas are there, just organize em,

OpenStudy (anonymous):

ok i will thanks so mcuh

OpenStudy (danjs):

overall the remaining unknown angles A and B have to total 90, so A can be 89.99999 and B the rest 0.00001 deg, and that works for example that statement will tell you what the possible values for sin and cos will be

OpenStudy (danjs):

0 < A < 90 0 < B < 90 sin(0) < sin(A) < Sin(90) 0 < sin (A) < 1

OpenStudy (danjs):

sme for cos(A) 0 < A < 90 sin(0) < sin ( A) < sin(90) 0 < sin (A) < 1

OpenStudy (danjs):

the hard part is remembering all the 'official' names for properties and stuff for the reasons

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!