I need help with these. I will fan and medal 1) Kelly tells you that when variables are in the denominator, the equation one over two plus three over x equals three over four becomes unsolvable. Kelly explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to Kelly how the equation is still solvable and explain your reasoning.
cross multiple
multiply each term by 4x ( the LCD) is another way to do this
There are two strategies. one way is to add the fractions on the left using a common denominator of 2x The other way is to "clear the denominators" which is a fancy way to say "multiply the equation by the common denominator of all the terms" in this case 4x you would get this: \[ 4x\left( \frac{1}{2} + \frac{3}{x}= \frac{3}{4}\right)\\ \frac{1\cdot 4x}{2} + \frac{3\cdot 4x}{x}= \frac{3\cdot 4x}{4} \] and if you simplify each term you get \[ 2x +12= 3x \] now add -2x to both sides \[ 12=x \]
-1/2+1/2+3/x = 3/4-1/2 [add both sides -1/2] 3/x = 3/4 - 2/4 [ here i write 1/2 = 2/4] 3/x = 1/4 x/3 = 4/1 multiply both sides with 3 x = 12
I got this completely wrong earlier. I don't know what I was thinking. Sorry if I confused you! The above answers are correct.
This is hard, You sure?
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