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Algebra 18 Online
OpenStudy (anonymous):

I need help with these. I will fan and medal 1) Kelly tells you that when variables are in the denominator, the equation one over two plus three over x equals three over four becomes unsolvable. Kelly explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to Kelly how the equation is still solvable and explain your reasoning.

OpenStudy (anonymous):

OpenStudy (anonymous):

cross multiple

OpenStudy (welshfella):

multiply each term by 4x ( the LCD) is another way to do this

OpenStudy (phi):

There are two strategies. one way is to add the fractions on the left using a common denominator of 2x The other way is to "clear the denominators" which is a fancy way to say "multiply the equation by the common denominator of all the terms" in this case 4x you would get this: \[ 4x\left( \frac{1}{2} + \frac{3}{x}= \frac{3}{4}\right)\\ \frac{1\cdot 4x}{2} + \frac{3\cdot 4x}{x}= \frac{3\cdot 4x}{4} \] and if you simplify each term you get \[ 2x +12= 3x \] now add -2x to both sides \[ 12=x \]

OpenStudy (dayakar):

-1/2+1/2+3/x = 3/4-1/2 [add both sides -1/2] 3/x = 3/4 - 2/4 [ here i write 1/2 = 2/4] 3/x = 1/4 x/3 = 4/1 multiply both sides with 3 x = 12

OpenStudy (anonymous):

I got this completely wrong earlier. I don't know what I was thinking. Sorry if I confused you! The above answers are correct.

OpenStudy (anonymous):

This is hard, You sure?

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