Question

The length of a rectangle is 8 in. more than its width. The perimeter is 52 in.

What is the length of the rectangle?
@pooja195

Answer 1

\[\huge~\rm~L=w+8\]
The formula for perimeter is
\[\huge~\rm~P=2L+2w\]
We know that the perimeter is 52in

Answer 2

i dont understand

Answer 3

oh ok

Answer 4

Let's try an easier approach .-.
2L+2W=52 <---equation for perimeter
W=L-8 <---re-arranged equation for length

Answer 5

Basically take equation 2 and plug it in place of w in equation 1
\[\huge~\rm~2L+2(L-8)=52 \]
From here solve for L

Answer 6

4L(L-8)=52?

Answer 7

Can you show me the steps you did to get that so i can find your mistake?

Answer 8

i added 2L+2

Answer 9

Solve the following for L, the length :
2( (L-8) + L ) = 52

Answer 10

Ok
Start by distributing
2(L−8)
2 x L =2L
2 x -8=?

Answer 11

2x-8= -16?

Answer 12

Good
Good so now we have
\[\huge~\rm~2L+2L-16=52 \]
combine like terms

Answer 13

this is the part that always gets me

Answer 14

Combine the l's together
2+2=?

Answer 15

4L

Answer 16

Good
\[\huge~\rm~4L-16=52\]
now add 16 to both sides
52+16=?

Answer 17

4L=36

Answer 18

56+12=36?

Answer 19

?

Answer 20

52+16=?

Answer 21

68

Answer 22

4L=68 divide both sides by 4
4/4=1
just L
68/4=?

Answer 23

68/4=17

Answer 24

Good we we have L=17 :)

Answer 25

WOW Thank you

Answer 26

yw ^_^