Question

let f(x)=x^2+7 andg(x)=x+3/x. Find (g*f)(-5)

Answer 1

@aaronq @confluxepic @ganeshie8 @Luigi0210 @hartnn @Luigi0210

Answer 2

Plug in -5 for the x in f(x). Do the same for g(x). Multiply the two results

Answer 3

(-5)^2 + 7 = (answer)
g(x) (answer)+ 3 / (answer)
basically what @peachpi said

Answer 4

im stuck @Serenity74 did you get 32/35 or 35/12

Answer 5

Didn't calculate it wait a sec.

Answer 6

k @Serenity74

Answer 7

I didnt get 32/35

Answer 8

what you got @Serenity74

Answer 9

25 + 7 = 32 (x = 32)
32 + 3 = 35 (x +3)
Then it would be 35/x
So it would be 35/32

Answer 10

hint:
by definition of function of function, we can write this:
\[g\left( {f\left( x \right)} \right) = f\left( x \right) + \frac{3}{{f\left( x \right)}} = \left( {{x^2} + 7} \right) + \frac{3}{{{x^2} + 7}}\]
now, please replace \(x=-5\) at the right side

Answer 11

25 + 7 = 32 (x = 32)
32 + 3 = 35 (x +3)
Then it would be 35/x
So it would be 35/32

Answer 12

Do you get or no???

Answer 13

Do you get or no???

Answer 14

Do you get or no???

Answer 15

Do you get or no???

Answer 16

Do you get or no???

Answer 17

Do you get or no???

Answer 18

Do you get or no???