Question

Someone please help I'm having trouble understanding this

You are going to design an advertisement for a new polynomial identity that you are going to invent.


Label and display your new polynomial identity
Prove that it is true through an algebraic proof, identifying each step
Demonstrate that your polynomial identity works on numerical relationships

Column A | (x − y), (x + y), (y + x), (y − x)|
Column B | (x2 + 2xy + y2), (x2 − 2xy + y2), (ax + b), (cy + d)|

Answer 1

Create your own using the columns below. See what happens when different binomials or trinomials are combined. Square one factor from column A and add it to one factor from column B to develop your own identity.

Answer 2

Are you in FLVS?

Answer 3

yeah this is for algebra II

Answer 4

Step 1: New Identity
Create your own using the columns below. See what happens when different binomials or trinomials are combined. Square one factor from column A and add it to one factor from column B to develop your own identity.

(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Step 2: Proof
Check polynomial identity.

(ax+b)(x+a) = FOIL

(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)


+bx+ab is the Second Term in the FOIL
Then add both expressions together from First Term and Second Term =
ax^2 + a^2x + bx + ab
Step 3: Proof
Try with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126

Answer 5

Hope this helped! Have a great day!

Also a medal would be much appreciated! Just click best response next to my answer. Thank You!

@Ikou

Answer 6

(x+a) isn't in any of the columns though