Question

What volume in L of oxygen is required to burn 0.556L of propane if both gases are measured at the same temperature and pressure?

Answer 1

@whpalmer4

Answer 2

What is the formula for propane, and what is the balanced equation for the reaction?

Answer 3

C3H8

Answer 4

C3H8 + 5O2 ----> 3CO2 + 4H2O

Answer 5

ok, good. what do we know about moles of gas at the same temperature and pressure?

Answer 6

Avogadro's law says equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. That means we just need to figure out the ratio of moles of oxygen to moles of propane and then apply that same proportion to the quantity of propane we are burning.

Answer 7

If 1 mole of one of the reactants takes up x liters of space, then 2 moles of that reactant will take up 2x liters, and so on.

Answer 8

dont solve it.

Answer 9

I am working on it now.

Answer 10

Not my final answer. Those moles for propane doesn't look right?

Answer 11

Is that even right? That number seems very small..

Answer 12

2.78L of O2

Answer 13

My mole ratio was backwards

Answer 14

We need 5 moles of O2 for every 1 mole of propane, so if we have 0.556 L of propane, we need 5*0.556 = 2.78 L of O2.