y=–6x+2 –12x – 2y =–4 How many solutions does this linear system have? a.one solution: (0, 0) b.one solution: (1, –4) c.no solution d.infinite number of solutions
so you have to solve this one variable at a time what you can do is plug in the value of y in the first equation into the second then solve \(-12 x - [ 2\times (\color{red}{-6x+2})] = -4 \)
do you get it?
i cant figure it out
what can't you figure out?
how to solve it
I basically showed you half of the process already
i put it in a graph but didnt find any point intersecting i believe its no solution
okay, then there is NO solution LAUGHING HYSTERICALLY INSIDE MY HEAD
y=–6x+2 <--equation 1 –12x – 2y=–4 <---equation 2 btw no solution is incorrect Plug equation 1 into equation 2 since the value of y is given -12x-2(-6x+2)=-4 solve for x
i solve the parantheis first?
correct
-18x-0=-4
No. Start by distributing \[\rm~−12x+(−2)(−6x)+(−2)(2)=−4 \]
Write the equation u have left
i did distribute thats how i got that
Show me.
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