y=–6x+2
–12x – 2y =–4
How many solutions does this linear system have?
a.one solution: (0, 0)
b.one solution: (1, –4)
c.no solution
d.infinite number of solutions
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OpenStudy (nincompoop):
so you have to solve this one variable at a time
what you can do is plug in the value of y in the first equation into the second then solve
\(-12 x - [ 2\times (\color{red}{-6x+2})] = -4 \)
OpenStudy (nincompoop):
do you get it?
OpenStudy (karolynxx):
i cant figure it out
OpenStudy (nincompoop):
what can't you figure out?
OpenStudy (karolynxx):
how to solve it
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OpenStudy (nincompoop):
I basically showed you half of the process already
OpenStudy (karolynxx):
i put it in a graph but didnt find any point intersecting i believe its no solution
OpenStudy (nincompoop):
okay, then there is NO solution
LAUGHING HYSTERICALLY INSIDE MY HEAD
pooja195 (pooja195):
y=–6x+2 <--equation 1
–12x – 2y=–4 <---equation 2
btw no solution is incorrect
Plug equation 1 into equation 2 since the value of y is given
-12x-2(-6x+2)=-4
solve for x
OpenStudy (karolynxx):
i solve the parantheis first?
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pooja195 (pooja195):
correct
OpenStudy (karolynxx):
-18x-0=-4
pooja195 (pooja195):
No.
Start by distributing
\[\rm~−12x+(−2)(−6x)+(−2)(2)=−4 \]
pooja195 (pooja195):
Write the equation u have left
OpenStudy (karolynxx):
i did distribute thats how i got that
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