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Solve: 7^(x+3)=e^x
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how would you cancel out the `e` ? do you know ?
Natural log?
yes right take ln log both sides and then apply the ln rule
So then it is ln7^(x+3)=x?
looks good so far
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Then it would be (x+3)ln7=x
perfect i'm pretty sure you can handle it from there :=))
And that's where I'm lost on what to do next I thought to divide by x+3
@nnesha
haha okay you have to solve for x how would you do that ? dividing by x+3 is basically solving for ln 7 but we need to solve for x
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Omg never mind I had a blonde moment
X=-6.17
looks good
Thank you! @nnesha
np :=)) good job!
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