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Mathematics 20 Online
OpenStudy (anonymous):

Solve: 7^(x+3)=e^x

Nnesha (nnesha):

how would you cancel out the `e` ? do you know ?

OpenStudy (anonymous):

Natural log?

Nnesha (nnesha):

yes right take ln log both sides and then apply the ln rule

OpenStudy (anonymous):

So then it is ln7^(x+3)=x?

Nnesha (nnesha):

looks good so far

OpenStudy (anonymous):

Then it would be (x+3)ln7=x

Nnesha (nnesha):

perfect i'm pretty sure you can handle it from there :=))

OpenStudy (anonymous):

And that's where I'm lost on what to do next I thought to divide by x+3

OpenStudy (anonymous):

@nnesha

Nnesha (nnesha):

haha okay you have to solve for x how would you do that ? dividing by x+3 is basically solving for ln 7 but we need to solve for x

OpenStudy (anonymous):

Omg never mind I had a blonde moment

OpenStudy (anonymous):

X=-6.17

Nnesha (nnesha):

looks good

OpenStudy (anonymous):

Thank you! @nnesha

Nnesha (nnesha):

np :=)) good job!

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