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Mathematics
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How do I solve this?
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Start by drawing a figure. Draw a rectangle that is wider than high. Draw a diagonal.
|dw:1449683731535:dw|
Great. Now we look at it as if the length really were 16 in. and the height 9 in. Let's label it. |dw:1449683787154:dw|
If the TV had width 16 in. and height 9 in., what would the diagonal be?
Are you familiar with the Pythagorean theorem?
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Yes, \[16^2+9^2\]
256+81=337
Correct. What is that equal to?
\[\sqrt{337}=18.35755\]
Great. Let's add that to our figure too. |dw:1449684141919:dw|
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Ok. A TV 16 in. by 9 in. has a diagonal 18.37 in. Now you can do a proportion. If a diagonal of 18.36 in. has a height of 9 in., a diagonal of 50 in. has a height of x. Use a proportion to find x.
Alright, |dw:1449684384802:dw|
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