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Mathematics 13 Online
OpenStudy (shaleiah):

How do I solve this?

OpenStudy (mathstudent55):

Start by drawing a figure. Draw a rectangle that is wider than high. Draw a diagonal.

OpenStudy (shaleiah):

|dw:1449683731535:dw|

OpenStudy (mathstudent55):

Great. Now we look at it as if the length really were 16 in. and the height 9 in. Let's label it. |dw:1449683787154:dw|

OpenStudy (mathstudent55):

If the TV had width 16 in. and height 9 in., what would the diagonal be?

OpenStudy (mathstudent55):

Are you familiar with the Pythagorean theorem?

OpenStudy (shaleiah):

Yes, \[16^2+9^2\]

OpenStudy (shaleiah):

256+81=337

OpenStudy (mathstudent55):

Correct. What is that equal to?

OpenStudy (shaleiah):

\[\sqrt{337}=18.35755\]

OpenStudy (mathstudent55):

Great. Let's add that to our figure too. |dw:1449684141919:dw|

OpenStudy (mathstudent55):

Ok. A TV 16 in. by 9 in. has a diagonal 18.37 in. Now you can do a proportion. If a diagonal of 18.36 in. has a height of 9 in., a diagonal of 50 in. has a height of x. Use a proportion to find x.

OpenStudy (shaleiah):

Alright, |dw:1449684384802:dw|

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