Question

Find the given integral:
draw a picture and answer the question based on the picture.

Answer 1

\[\int\limits_{0}^{4} \sqrt{4-(x-2)^{2}} dx\]

Answer 2

@Hero @freckles @satellite73

Answer 3

@satellite73

Answer 4

\[y=\sqrt{4-(x-2)^2} \\ y^2=4-(x-2)^2, y\ge 0 \\ (x-2)^2+y^2=4,y \ge 0 \]

so you are only looking at top part of the circle

Answer 5

yes I need to kow the graph! plz help me with this one!

Answer 6

so you don't know how to draw the circle (x-2)^2+y^2=4?

Answer 7

this is in center-radius form....

Answer 8

(x-h)^2+(y-k)^2=r^2
center is (h,k)
r is radius

and we have y>=0 so erase bottom part of circle because it will fall below the y-axis