Question

The figure below shows a rectangle ABCD having diagonals AC and DB:

A rectangle ABCD is shown with diagonals AC and BD.

Jimmy wrote the following proof to show that the diagonals of rectangle ABCD are congruent:


Jimmy's proof:
Statement 1: In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent)
Statement 2: Angle ADC = Angle BCD (angles of a rectangle are 90°)
Statement 3:
Statement 4: Triangle ADC and BCD are congruent (by SAS postulate)
Statement 5: AC = BD (by CPCTC)

Answer 1

Which statement below completes Jimmy's proof?
AB=AB (reflexive property of equality) AB=AB (transitive property of equality) DC=DC (reflexive property of equality) DC=DC (transitive property of equality)

Answer 2

@souleaterz @Anaise @callielovesyhuu @CallMeKiki @ganeshie8

Answer 3

@celinegirl @Christian_10_ @Elsa213