Question

SOMEONE PLEASE HELP ME!!CHEMISTRY! FAN MEDAL!

1. 4NH3 + 5O2 4NO +6H2O

In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2. How many grams of NO are formed?

________
Please round final answers to the tenth position, one place after the decimal. Please remember your units.


2. 2 CuCl2 + 2 NaNO3 ---> Cu(NO3)2 + 2 NaCl



If 15 grams of copper (II) chloride react with 20 grams of sodium nitrate, How many grams of NaCl is formed?

Answer 1

4NH3 + 5O2 4NO +6H2O
3.25 g of NH3 are allowed to react with 3.50 g of O2. How many grams of NO are formed?
We know from this reaction that 4 moles of ammonia react with 5 moles of Oxygen gas to Form 4 moles of Nitrogen oxide and water.
So we have to make the convention from grams to moles, for that you have to get your periodic table and calculate the masses of each compound.
NH3 has a molar mass of 17.0 g/mol
So ask yourself: if 17.0g is equal to 1 mol, 3.25 g is equal to how many moles?

Once you've covered the mole conversion think what's the limiting reactant

Answer 2

The molar mass of Oxygen gas is 16.0 g/ mol.
3.50g/16g=×mol/1mol
So from the calculated moles follow the stoichiometry and think that you will have x given moles of Nitrogen oxide depending on which one is your limiting reactant

Answer 3

So the answer is 4.58 mol? @tatianagomezb

Answer 4

Im sorry 4.57

Answer 5

Must be, sorry. I can't check that right now, that's why I didn't put the actual answers. After that you have to convert the moles to grams again. But only for the product you need, in this case NO.