An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.
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OpenStudy (cheybree1107):
@pooja195
OpenStudy (cheybree1107):
@Luigi0210 @Nnesha
OpenStudy (cheybree1107):
@RAM231
OpenStudy (ram231):
I have NO clue. Im sorry I can't figure out the equation to use with it.
OpenStudy (cheybree1107):
@Nerdsarecool
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OpenStudy (nerdsarecool):
Is this the question
OpenStudy (nerdsarecool):
Ok so tell me in your words what is the question asking
OpenStudy (cheybree1107):
that's the exact question copied and pasted
OpenStudy (nerdsarecool):
Oh ok
OpenStudy (nerdsarecool):
So what is the tip at what degrees
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OpenStudy (nerdsarecool):
Give me a sec
OpenStudy (nerdsarecool):
So i will be right back i need to go eat and then i will figure out how to answer the question
OpenStudy (nerdsarecool):
Got it
OpenStudy (nerdsarecool):
x tan q
OpenStudy (nerdsarecool):
That is the answer
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OpenStudy (nerdsarecool):
x tan q
OpenStudy (cheybree1107):
options are x/ tan q, x/ sin q, x tan q, x sin q, or x cos q
OpenStudy (nerdsarecool):
A
OpenStudy (nerdsarecool):
x/tan q
OpenStudy (nerdsarecool):
I am sure
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OpenStudy (nerdsarecool):
I have to go but the answer is x/tan q
OpenStudy (cheybree1107):
thanks!
OpenStudy (nerdsarecool):
np
OpenStudy (nerdsarecool):
I have to go eat dinner but your welcome for the answer