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Mathematics 12 Online
OpenStudy (cheybree1107):

An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.

OpenStudy (cheybree1107):

@pooja195

OpenStudy (cheybree1107):

@Luigi0210 @Nnesha

OpenStudy (cheybree1107):

@RAM231

OpenStudy (ram231):

I have NO clue. Im sorry I can't figure out the equation to use with it.

OpenStudy (cheybree1107):

@Nerdsarecool

OpenStudy (nerdsarecool):

Is this the question

OpenStudy (nerdsarecool):

Ok so tell me in your words what is the question asking

OpenStudy (cheybree1107):

that's the exact question copied and pasted

OpenStudy (nerdsarecool):

Oh ok

OpenStudy (nerdsarecool):

So what is the tip at what degrees

OpenStudy (nerdsarecool):

Give me a sec

OpenStudy (nerdsarecool):

So i will be right back i need to go eat and then i will figure out how to answer the question

OpenStudy (nerdsarecool):

Got it

OpenStudy (nerdsarecool):

x tan q

OpenStudy (nerdsarecool):

That is the answer

OpenStudy (nerdsarecool):

x tan q

OpenStudy (cheybree1107):

options are x/ tan q, x/ sin q, x tan q, x sin q, or x cos q

OpenStudy (nerdsarecool):

A

OpenStudy (nerdsarecool):

x/tan q

OpenStudy (nerdsarecool):

I am sure

OpenStudy (nerdsarecool):

I have to go but the answer is x/tan q

OpenStudy (cheybree1107):

thanks!

OpenStudy (nerdsarecool):

np

OpenStudy (nerdsarecool):

I have to go eat dinner but your welcome for the answer

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