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(Mitx Ungraded question-Acids and bases!) The value of pKa for acetic acid, CH3COOH (aq), is 4.75. Calculate the pH and the pOH of 1.1 M CH3COOH (aq) in water.
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-A) find pH -B) find pOH Unfortunately, I don't have a clear idea of how to go about this. I know that I have to find the ratios, and subtract the PH from ?14?. But other than that I'm clueless. Thanks in advance!
Write a the dissociation equation, make an I.C.E. table and use the \(K_A\) in an equilibrium expression to solve for \(H^+\). from there use: \(\sf pH=-log[H^+]\) and \(\sf pH+pOH=14\)
Thank you! I managed to solve it! c:
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