Question

If f(x)=2−x^1/2 and g(x)=x^2−9, what is the domain of g(x)÷f(x)?

Answer 1

Can you show me the result expression for \(\frac{ g(x) }{ f(x) }\)?

Answer 2

Nope

Answer 3

In the form I gave you, write down the expressions representing f(x) and g(x) respectively.
That way you'll obtain the mathematical expression that represents the division of g(x) by f(x).

Answer 4

Here's the problems and anwsers if i didnt type it right.

Answer 5

I will not provide you with any answers, I will guide you throuh the solution of the problem.

Answer 6

\[x^2-9/2-x^1/2\]

Answer 7

I dont know how do use the equation thing but i know what you mean

Answer 8

it is not "minus" but a division, meaning that, for instance: \[p \div q \iff \frac{ p }{ q }\]
it's a way to express it.

Answer 9

I dont understand

Answer 10

if you are asked to express \(\frac{ g(x) }{ f(x) } \) and you know that the functions regarding g(x) and f(x) have the structures \(g(x)=x^2-9\) and \(f(x)=x ^{\frac{ 1 }{ 2 }}\) respectively. Then it's just a matter of plugging them in.

Answer 11

I am plugging them in its not giving me an answer thats a choice.

Answer 12

I am not telling you this is an answer, what I want you to do is to express the expression and then tell me what the domain of \((\frac{ g }{ f })(x)\).

To put it more simple, in any rational function, what is the factor that can cause it to become undefined?

Answer 13

I dont know.

Answer 14

A more orienting question, what is the result of \(\frac{ 3 }{ 0 }\) ?

Answer 15

0

Answer 16

That's incorrect, try plugging it in a calculator.

Answer 17

Well i dont know how to do it your not helping me at all just making me more confused

Answer 18

@EmiilyMxo appreciate the help you get if you dont understand say you dont understand rather than being rude. Tell the helper you dont understand you also need to make an effort to attempt to get the answer. Don't expect the answer to be given to you like a cookie. This is is openstudy not openanswers.

Answer 19

I'm trying to get an answer thanks for the help anyway

Answer 20

Then I guess you're on your own. No one will want to help you if you are simply looking for answers. Can we try this again? And participate a bit more? ^.^

Answer 21

Nope to late

Answer 22

Awww . Good luck in the future. :)

Answer 23

I have already been issued by professors of online courses a couple of times for giving answers, and so did OS.
And we are helpers, not answer givers; OS nor the helpers will contribute to you cheating in your assignments.

Answer 24

Thanks for the "help" :))