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Given the position function, s(t) = t^3/3 - 12t^2/2 +36t, between t = 0 and t = 15, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right. 0 < t < 6 5 < t < 15 t > 15 The particle always moves to the right.
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@Conqueror
hint: if the particle is moving to the right, then the function \(s(t)\) is an increasing function, namely its first derivative is greater than zero
so it's 0 < t < 6 @Michele_Laino
yes! That's right!
Thank you ;)
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