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OpenStudy (ofmiceparade):
When looking at a rational function f of x equals the quantity x plus three times the quantity x minus two times the quantity x plus five all divided by the quantity x minus three times the quantity x plus two times the quantity x minus 5, Charles and Bobby have two different thoughts. Charles says that the function is defined at x = –2, x = 3, and x = 5. Bobby says that the function is undefined at those x values. Who is correct? Justify your reasoning.
OpenStudy (ofmiceparade):
Hey
OpenStudy (ofmiceparade):
@Sushi121212 @clippone25 @ItsKoreyyy
OpenStudy (ofmiceparade):
Pls boss
Help
OpenStudy (ofmiceparade):
@HarleyQuinn98
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OpenStudy (ofmiceparade):
OpenStudy (harleyquinn98):
idk
OpenStudy (ofmiceparade):
Im not typing btw
it just says i am
OpenStudy (ofmiceparade):
^
OpenStudy (denonakavro):
Charles is right because the solutions are the zeroes of the denominators
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OpenStudy (ofmiceparade):
Can you jusitfy the reasoning? @denonakavro
OpenStudy (denonakavro):
So (x+2)(x-3)(x-5) will be defined as -2, 3, 5
OpenStudy (denonakavro):
Justification ( I am kinda sure):
The following equation will be defined at -2, 3, 5 because those are the zeroes where the denominator will be 0