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Mathematics 20 Online
OpenStudy (haleyelizabeth2017):

Given the graphs of the linear function, f(x), and the quadratic equation, g(x), evaluate: (f+g)(2) http://imgur.com/VDMd5lX

OpenStudy (solomonzelman):

You probably know that \(\color{#000000 }{ \displaystyle (f+g)(x)=f(x)+g(x) }\) and therefore \(\large\color{#000000 }{ \displaystyle (f+g)(2)=f(2)+g(2) }\)

OpenStudy (haleyelizabeth2017):

Yes :)

OpenStudy (haleyelizabeth2017):

And I know f(x)=x right?

OpenStudy (solomonzelman):

Well, yes, but you don't really need that though

OpenStudy (solomonzelman):

You can find the y-value that corresponds to f(2) and to g(2) on the picture/graph.

OpenStudy (solomonzelman):

|dw:1450294142201:dw|

OpenStudy (haleyelizabeth2017):

-4 and 2 actually...

OpenStudy (solomonzelman):

|dw:1450294151696:dw|

OpenStudy (haleyelizabeth2017):

So, do we just add those?

OpenStudy (solomonzelman):

yes, you need (f+g)(2), which as I said is same as: f(2)+g(2)

OpenStudy (solomonzelman):

So your final answer is?

OpenStudy (haleyelizabeth2017):

okay, so it would be -2

OpenStudy (solomonzelman):

Yup, -2 is the very final answer!

OpenStudy (haleyelizabeth2017):

Thank you :)

OpenStudy (solomonzelman):

good job

OpenStudy (haleyelizabeth2017):

LOL you did all the work XD

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