Please help! a+b=5 b+c=-2 c+a=7 Solve
you can isolate 'a' in the third equation c+a=7 c+a-c=7-c ... subtract 'c' from both sides a = 7-c then plug this into the first equation a+b=5 7-c+b=5 ... replace 'a' with 7-c 7+b-c = 5 7+b-c-7 = 5-7 ... subtract 7 from both sides b-c = -2
after doing all that, we end up with this system of equations b+c=-2 b-c = -2 do you see what to do next?
I understand so far but I don't know what to do next.
try adding the 2 equations and what do you get ?
notice that the c's cancel
b=-4 ?
yep
you forgot to add the b terms b+b = 2b
oops..my bad....sorry, I missed that
so if 2b = -4, then b = ???
b=-2
yes....now sub -2 in for b in the other equations to find the other letters
a=7 and c=0 ?
so we have this claim a = 7 b = -2 c = 0 let's test that claim with each equation Testing equation 1: a+b = 5 7+(-2) = 5 ... plug in a = 7 and b = -2 5 = 5 ... true Testing equation 2 b+c = -2 -2+0 = -2 ... plug in b = -2 and c = 0 -2 = -2 ... true Testing equation 3 a+c = 7 7+0 = 7 ... plug in a = 7 and c = 0 7 = 7 ... true All three equations are true when a = 7, b = -2 and c = 0. So the solution (a,b,c) = (7,-2,0) is confirmed
whenever you get a possible solution, it's always a good idea to check that possible solution back into the original equation(s) to see if it's a true solution or not
okay thank you so much!
you're welcome
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