Probability question: A bag contains 12 coloured balls. Five of the balls are red and the rest are blue. A ball is drawn at random from the bag. It is then replaced and a second ball is drawn. The colour of each ball is recorded. The first question asks me to list the possible outcomes of the experiment which I did without problems. The next one however, is where I am stuck. (b) Calculate the probability that: (i) The first ball is blue
5 - red 12-5=7 blue Ball is randomally drawn twice with replacement.
BR BB RB RR those are possible outcomes, (and would have been even without replacement)
(b) probability of what?
The probability that the first ball is blue
The answer is given as 7/12 but I don't know how they got there
7 blue out of 12balls
Oh...I don't know how I missed that...
Well ok then. Thanks very much.
no problem
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