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OpenStudy (anonymous):
What is the period of y = cot x?
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OpenStudy (anonymous):
\[A. 2\pi\]
\[B. \pi/2\]
\[C. \]
\[D. 1/\]
OpenStudy (mathmale):
I'd suggest you graph y=tan x. This basic trig function has the same period as its cofunction y=cot x.
OpenStudy (anonymous):
I agree with Mathmale
OpenStudy (mathmale):
Are y ou sure you've copied down the four possible answers correctly?
You show nothing for C.
OpenStudy (anonymous):
Spikers want me to show you the work i got then you can compare and contrast it to the work you have
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OpenStudy (anonymous):
From graphing it, I get \[\pi\]
OpenStudy (anonymous):
Let's solve for c.
y=cotx
Step 1: Flip the equation.
cotx=y
Step 2: Divide both sides by otx.
cotx
otx
=
y
otx
OpenStudy (anonymous):
thats my work useing that i want you to solve it and i will tell you whether or not your right
OpenStudy (anonymous):
it's pi
OpenStudy (anonymous):
\[\pi\]
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OpenStudy (anonymous):
ya the answers didnt copy correcly, C. was pi
OpenStudy (anonymous):
@Lord_Frieza @mathmale
OpenStudy (anonymous):
k
OpenStudy (anonymous):
i was tagged
OpenStudy (anonymous):
Did you get pi ?
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OpenStudy (anonymous):
i got b
OpenStudy (anonymous):
i could be wrong tho
OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
it is blood
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OpenStudy (mathmale):
@Lord_Frieza: Lay off, please. Spikers found the correct answer on his own minutes ago, through graphing. More power to him.
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