Question

How do you graph one cycle of y=(sin x/2)^2

Answer 1

well the graph moves up... the centre of the curve is y = 0.5 and the max value is y = 1 and the minvalue is y = 0

now find the period of the curve

for

\[y = sin(bx) \]

the period is found using

\[\frac{2\pi}{b}\]

you have b = 0.5 or 1/2

so substitute it and find the period.

that is the distance you need on the x - axis for 1 cycle

hope it helps