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Solve for x. 6x - 3 + 12 = 5x + 24 - 4x A. x = -5 B. x = 2 C. x = 5 D. x = 3
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Start by combining like terms
Combining? You mean adding 5 on both sides or?
\[\huge~\rm~(6x)+(−3+12)=(5x−4x)+(24)\]
6x remains the same since nothing can be combined with it -3+12=?
-3 + 12 = 9
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Good \[\huge~\rm~6x+9=(5x−4x)+(24)\] Now the other side 5x-4x=?
5x-4x=1x
Good and 24 remains the same \[\huge~\rm~6x+9=1x+24\] Ok whats the next step?
add 6x + 9?
Or am I diviiding?
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You cant add those remember combine like terms We would do this: |dw:1450499206733:dw|
Why would we be subtracting?
Because we want to get x by itself
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