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Calc help! Help its 3:17am and I'm crying
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Find the x-coordinates where f '(x) = 0 for f(x) = 2x + sin(4x) in the interval [0, π].
f(x) = 2x + sin(4x) f'(x) = ?
4cos(4x)+2
set that equal to 0
4cos(4x)+2 = 0 is same as cos(4x) = -1/2
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for what angles the cosine function spits out -1/2 ?
do i do arc cos?
you could do that
so 4x=arc cos -1/2?
Yes
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x=2.09?
Yes, leave it in exact form as 2pi/3
4x = 2pi/3
But wait, is that the only angle of cosine that gives -1/2 ?
add pi?
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