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Mathematics 8 Online
OpenStudy (sagewilson):

(image below) If AX:XB as AB:AC, find the missing length. AX = 5, XB = 4, AC = 6, find AB. 24/5 10/3 15/2

OpenStudy (sagewilson):

OpenStudy (owlcoffee):

The bisectrix theorem states, and I'll use this triangle as a reference that: \[\frac{ CA }{ CB }=\frac{ CX }{ XB }\]

OpenStudy (owlcoffee):

oops, make a mistake there: \[\frac{ AC }{ AB }=\frac{ CX }{ XB }\]

OpenStudy (sagewilson):

Okay, so it would look like this? 5/4 = ?/6 and I'm guessing that I would have to multiply 5 and 4 leaving me with 20 = ? * 6 ?

OpenStudy (sagewilson):

Is this ^ correct?

OpenStudy (sagewilson):

Wait if I am correct wouldn't the answer be 10/3?

OpenStudy (owlcoffee):

I would first use the given relationships in order to rewrite eveything to find the missing and asked-for side.

OpenStudy (sagewilson):

so is what I put correct? I'm still not sure if I am doing this correct.

OpenStudy (owlcoffee):

Well you are given the relationship: \[\frac{ AX }{ XB }=\frac{ AB }{ AC }\] You are given the corresponding sides, am I wrong? All is just to plot it: \[\frac{ 5 }{ 4 }=\frac{ AB }{ 6 }\] now it is just a matter to solve for AB.

OpenStudy (sagewilson):

Okay, so it would be 5*6 = 4*AB 30 = 4*AB 30/4 = 4/4 *AB this would leave me with 7.5 = AB, 7.5 as a fraction equals 15/2. so 15/2 is the answer. Thank you for your help. :)

OpenStudy (owlcoffee):

Great job!

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