MOnty HAll problem
You are confronted by 3 doors. Behind one of them is a car, behind the two others, you will only see a goat. Now, if you correctly pick the car, you win the car ! Otherwise, if you get one of the 2 goats, you don't get the car. So, pick any door. It doesn't matter which one, but I will suppose that you picked door #3, as an example. Should You switch? Now, after you have picked a door and before finding out what is actually behind it, you are shown a goat behind one of the other doors. (Remember there has to be a goat in 1 of the doors that you have not picked. ) Let's say you choose door #3. And also let’s say there's a goat in door 1. The question and the riddle is: should you switch the door that you picked? In other words, in this example, should you now choose door #2? Or, should you stick with your first choice (door #3)?
im going with 3 for no particular reason besides that i picked it in the first place. otherwise im clueless on this one :/
its a very famous monty hall problem
u choose what anyone else would have chosen
see when u choose for the first the probability of u getting a car was 1/3 so that means it was highly likely u chose the wrong door
then once the door of one goat was shown now u have a 50/50 chance
that means switching was the best thing so door 2
probabilities are fun :P
yup they are :) hope u liked it
reading into it on wikipedia and its actually very interesting. if the game show host follows the standards of game shows, then following that logic 2/3 times you will get the car.
yup
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