Can someone PLEASE help me out with these 4 math questions!?
one by one please.. don't post the rest now
I posted one. I don't know how to solve these kinds of problems.
\(1.\) Use the slope formula to find the slope (\(m\)). \(2.\) Choose one of the points (I will call it \( (a,b) \). Then, with a point \( (a,b) \) and slope \(m\), the equation of the line would be \(y-b=m(x-a)\) (point-slope form) \(y=mx+b-ma\) (slope intercept form)
The slope formula is: \( \color{black}{ \displaystyle {\rm m}=\frac{\color{blue}{{\rm y}_1}-\color{red}{{\rm y}_2}}{\color{green}{{\rm x}_1}-\color{darkgoldenrod}{{\rm x}_2}} }\) where, \(\color{black}{ \displaystyle {\rm m} }\) is the slope \(\color{black}{ \displaystyle (\color{green}{{\rm x}_1}~,~~\color{blue}{{\rm y}_1}) }\) and \(\Large\color{black}{ \displaystyle (\color{darkgoldenrod}{{\rm x}_2}~,~~\color{red}{{\rm y}_2}) }\) are your two points.
I will give you an example
Suppose that I want to find an equation of the line that goes through (4,3) and (5,16) I will apply the slope formula to find the slope \(\color{#000000 }{ \displaystyle m=\frac{16-3}{5-4}=\frac{13}{1}=13 }\) And then, I will use the point (4,3) to find the equation of the line, \(\color{#000000 }{ \displaystyle y-3=13(x-4) }\)
Then, in your problem you are shown the two points on the line, so use that information to find the equation of the line...
I think using your example, the answer is A. I'm not 100% sure though.
u still need help
Oh. Sorry! That was correct...
incorrect*
A is incorrect!
Can you show me your work please, so that I can track the error....
I didn't do any work, option A just fit with the chart you made. I thought it was it.
well, A is incorrect...
Can you try to do the same work as I did?
Uhh. sure I guess. Gimme a sec
Yes, let's first find the slope of this graph which is y2-y1 ---- x2-x1, as mentioned
Is it D. -7x+6y=-11 ??
I didn't get that answer. Do you have the steps? Maybe I can see the error
Thank you for helping me. :)
Join our real-time social learning platform and learn together with your friends!