Question

http://prntscr.com/9h42ly

Answer 1

@MARC_

Answer 2

@Directrix

Answer 3

What about y = (1-x)/(x - 2) ? How does that graph look? @MARC_ @Diana.xL

Answer 4

Is that y = -1/((x - 2) ?

Answer 5

The first graph goes negative quickly for x < 2. It has to stay positive.

Answer 6

would it be like this? http://prntscr.com/9h4be5

Answer 7

On that one, the right branch stays negative but the left branch is positive and then goes negative so it will not work.

Answer 8

What about this y = -1/(x - 2)

Answer 9

^^ If x <2, then y < 0.
If x > 2, then y <0.

The x-axis is a horizontal asymptote.

x = 2 is a vertical asympote.

Answer 10

Graph of DxL

Answer 11

@Diana.xL Graph this on the software you have and see how it looks.

y = -1/(x - 2)

Answer 12

That is the same as y = 1/(2 - x).

Answer 13

thnx