Can someone check this out.. so confused?

Question

askme12345 · Answer

@SolomonZelman @TheSmartOne @IrishBoy123

irishboy123 · Answer

i reckon there's no such thing as a typical sized room. 

maybe they just want to test your ability to size things up so you could -- totally making these numbers up --  assume that the "typical" room is 5m x 5m and 2.5m high.  ***to some, that's a room; to others, that's a castle.***

$V_R = 5 \times 5 \times 2.5 \; m^3$

a tennis ball is very roughly 5cm in diameter so has vol $V_B={4\over 3}\pi \; ({0.05\over 2})^3$ 

but you are only allowed to use 75pc of the space so discount $V_R$ by that amount.

$V_{R-actual} = 0.75 \times 5 \times 5 \times 2.5 \; m^3$

that should get you [tennis]ballpark,.....forgiving the terrible pun.