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Mathematics 13 Online
Zeronknight (zeronknight):

Solve this inequality: \LARGE -x < 5 A. \LARGE x > 5 B. \LARGE x < -5 C. \LARGE x > -5 D. \LARGE x < 5

pooja195 (pooja195):

Divide both sides by -x

pooja195 (pooja195):

As in the previous one we were trying to isolate x, same concept here

pooja195 (pooja195):

-x means -1 \[\huge~\rm~\bf~-x/-1< 5/-1 \]

Zeronknight (zeronknight):

ok

OpenStudy (anonymous):

ok so whenever a negative sign is divided the equality sign changes

Zeronknight (zeronknight):

5 / -1 = -5?

Zeronknight (zeronknight):

Divide both sides.

pooja195 (pooja195):

Yes correct

Zeronknight (zeronknight):

Lol!! Pooja please :P

pooja195 (pooja195):

-x/-1<-5

pooja195 (pooja195):

Whats next? :)

Zeronknight (zeronknight):

What's next? Deleting my responses? jk jk. x / 1?

Zeronknight (zeronknight):

x / -1*

pooja195 (pooja195):

Yes what is -1/-1=?

Zeronknight (zeronknight):

-1? or 0

pooja195 (pooja195):

-1/-1=1 Because when we divide a negative by a negative it becomes a postitive

Zeronknight (zeronknight):

oh

pooja195 (pooja195):

x<-5 BUT WAIT THERE'S MORE :D

Zeronknight (zeronknight):

that caps doe

pooja195 (pooja195):

When we have divide by a negative we FLIP the SIGN SO \[\huge~\rm~\bf~< \rightarrow > \]

pooja195 (pooja195):

So what would our answer be? :)

Zeronknight (zeronknight):

X > -5

pooja195 (pooja195):

Yes! Perfect! :)

Zeronknight (zeronknight):

Thank you Professor. :P

pooja195 (pooja195):

yw ^_^

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