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Zeronknight (zeronknight):
Solve this inequality:
\LARGE -x < 5
A. \LARGE x > 5
B. \LARGE x < -5
C. \LARGE x > -5
D. \LARGE x < 5
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pooja195 (pooja195):
Divide both sides by -x
pooja195 (pooja195):
As in the previous one we were trying to isolate x, same concept here
pooja195 (pooja195):
-x means -1
\[\huge~\rm~\bf~-x/-1< 5/-1 \]
Zeronknight (zeronknight):
ok
OpenStudy (anonymous):
ok so whenever a negative sign is divided the equality sign changes
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Zeronknight (zeronknight):
5 / -1 = -5?
Zeronknight (zeronknight):
Divide both sides.
pooja195 (pooja195):
Yes correct
Zeronknight (zeronknight):
Lol!! Pooja please :P
pooja195 (pooja195):
-x/-1<-5
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pooja195 (pooja195):
Whats next? :)
Zeronknight (zeronknight):
What's next? Deleting my responses? jk jk.
x / 1?
Zeronknight (zeronknight):
x / -1*
pooja195 (pooja195):
Yes
what is -1/-1=?
Zeronknight (zeronknight):
-1? or 0
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pooja195 (pooja195):
-1/-1=1
Because when we divide a negative by a negative it becomes a postitive
Zeronknight (zeronknight):
oh
pooja195 (pooja195):
x<-5
BUT WAIT THERE'S MORE :D
Zeronknight (zeronknight):
that caps doe
pooja195 (pooja195):
When we have divide by a negative we FLIP the SIGN
SO \[\huge~\rm~\bf~< \rightarrow > \]
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pooja195 (pooja195):
So what would our answer be? :)
Zeronknight (zeronknight):
X > -5
pooja195 (pooja195):
Yes! Perfect! :)
Zeronknight (zeronknight):
Thank you Professor. :P
pooja195 (pooja195):
yw ^_^
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