Question

algebra

Answer 1

@imqwerty

Answer 2

use slope formula m=(y-y)/(x-x) to find the slope. Then plug in one of the points, like
(3, 2500) into the point-slope formula y-y=m(x-x), and solve.

Answer 3

set the equation so i can solve it

Answer 4

okay just use the 2point form of st lines
okay so if u got 2 points \((x_1,~y_1)\) and \((x_2,~y_2)\) then the line can be written as-
\(\Large \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}\)

okay so just take any 2 beautiful points
okay i took these 2- \((3,2500)\) and \((5,3000)\)
then just put them in equation and simplify to get answer in required form

Answer 5

m=(3000-2500)/(5-3)

Answer 6

thanks give me a second

Answer 7

m=250

Answer 8

y-2500=250(x-3)

Answer 9

y=250x+1750

Answer 10

yes

Answer 11

its not letting me plug 250 on the green box

Answer 12

I don't know...the equation is right.

Answer 13

yeah i have 3 days trying to to solve this one

Answer 14

the equation was wrong

Answer 15

I believe the problem is that to find the equation of a trend line you must use the starting point and the ending point, rather than 2 random points. So you would want the slope between (14, 5800) and (3, 2500).

Answer 16

alpha can you set up that equation for me please

Answer 17

шеы 300

Answer 18

*it's

Answer 19

so, y-2500=300(x-3)

Answer 20

y=300x+1600

Answer 21

Right. The equation to find the slope would have been:
m=(5800-2500)/(14-3)

And then Susanna's steps are right.

Answer 22

i still can't find the next step answer

Answer 23

Did the picture you posted mean that 312.5 was the correct slope that they wanted?

Answer 24

the other part

Answer 25

Ah! I have found what we did wrong. It specifically tells you to use the data from 1988 and 1996 to find your trend line, which means it is the points (3,2500) and (11,5000). So, your slope formula would be:
m=(5000-2500)/(11-3)=2500/8=312.5
Which is the answer you already have. To find the second part, we put it into point-slope form, which is:
\[y-y _{1}=m(x-x _{1})\]
Let's choose (3,2500) as our point, so:
\[(x _{1},y _{1})=(3,2500)\]

Can you plug these values in and solve now?

Answer 26

how can i plug those in?

Answer 27

So we have a value for m:
m=312.5
We have a value for x1:
\[x _{1}=3\]
And we have a value for y1:
\[y _{1}=2500\]
You can plug these values into the formula:
\[y-y _{1}=m(x-x _{1})\]
And then simplify to get the answer.