The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form of the equation for this line?
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pooja195 (pooja195):
y=mx+b <----slope intercept form
y=-x+6 <----what is the slope in the equation?
m=slope
OpenStudy (allgemeine-klause01):
srry the code sucks its supposed to be y= -2/3x+6
pooja195 (pooja195):
y=mx+b <----slope intercept form
y=-2/3x+6 <----what is the slope in the equation?
m=slope
OpenStudy (allgemeine-klause01):
-2
pooja195 (pooja195):
keep in mind that -2/3 is a fraction it belongs together
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OpenStudy (allgemeine-klause01):
oh -2/3
pooja195 (pooja195):
This is point slope form
\[\huge y-y_1=m(x-x_1)\]
where
m=-2/3 <---we know this from the slope intercept problem
(x1,y1)
(-3,8)
x1=?
y1=?
OpenStudy (allgemeine-klause01):
x1=-3 y1=8
pooja195 (pooja195):
Good now plug those numbers where they belong into the formula! :)
\[\huge y-y_1=m(x-x_1)\]
where
m=slope
(x1,y1)
pooja195 (pooja195):
We know that:
x1=-3
y1=8
m=-2/3
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