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Mathematics 14 Online
OpenStudy (anonymous):

Will medal look in comments for problem.

OpenStudy (anonymous):

OpenStudy (anonymous):

i have no brain now, give me a min.

OpenStudy (anonymous):

So far I changed it to \[5x+10y=1750\] \[2x+3y=600\] By multiplying the second equation by 6, but I don't know what to do now.

OpenStudy (anonymous):

sorry, 5

OpenStudy (anonymous):

I am confused guys, so you want me to divide the first equation by 5?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

the 5x+10y

OpenStudy (anonymous):

OK, so it would be x+2y=350 2x+3y=600

OpenStudy (anonymous):

yes, now multiply your first equation by 2 so you can eliminate x to solve.

OpenStudy (anonymous):

2x+4y=700 2x+3y=600 4y+3y=600+700 7y=1300 y=1300/7

OpenStudy (anonymous):

wait! 2x+4y=700 2x+3y=600 When eliminating, you minus it to get rid of the x. so you have 4y-3y=600+700 y=1300 now solve for x

OpenStudy (anonymous):

So, instead of adding 4y and 3y, I subtract them? And actually I already finished the problem correctly somehow, the answer was x=150 and y=100 I am still just trying to figure out the steps of how to solve.

OpenStudy (anonymous):

sorry, i made a mistake: 2x+4y=700 2x+3y=600 4y-3y=700-600 y=100

OpenStudy (anonymous):

yes, you subtract to eliminate x. How else would you do it. but to eliminate x (or y) the numbers have to be same.

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