Question

HELP PLZ ASAP:
Displacement versus Time

Answer 1

@imqwerty @robtobey

Answer 2

@Nerdsarecool @marieblossom16 @LegendarySadist @imqwerty

Answer 3

displacement is a length quantity and is measured in meters in SI unit system.
The unit of displacement given in graph is meter/seconds which is thus wrong.

Answer 4

yeah :)

Answer 5

thanks!

Answer 6

@imqwerty what about this one really quick i am stuck: An object starts from rest and accelerates at a rate of 3.0 m/s/s for 6.0 seconds. The velocity at the end of the 6.0 seconds is

0.50 m/s
1.0 m/s
2.0 m/s
18 m/s

Answer 7

use this formula-
\(\large v=u+at\)

here \(v\)-->final velocity
\(u\) -->initial velocity
\(a\)-->acceleration
\(t\)--->time period

Answer 8

i got 2.0

Answer 9

what values of \(u\), \(a\) and \(t\) did you put in the equation?

Answer 10

U= 3, a=6 and t= 6

Answer 11

the object starts from rest
it means that it was standing still initially
so the initial velocity \(u\) will be 0

it is given that the acceleration \(a\) is \(3m/s^2\)
and that time \(t\) is \(6secs\)

so now you have ->\(u\)=0
\(a\)=3
\(t\)=6

try to find \(v\) now

Answer 12

i got 9 but then I am not sure what'v' is again.... to divide by

Answer 13

\(v\) is the final velocity
the velocity at the end of 6 seconds

Answer 14

\(v=u+at\)

just substitute the values of \(u\) , \(a\) and \(t\) in this to get \(v\)

do you know what those values are?

Answer 15

why did you put that 6 on the left hand side?
\(\color{red}6=0+3(6)\)

you put that 6 in place of \(v\)
but well..we don't know what is \(v\) so we just put \(v\) in its place and solve for it using the equation

only this
6 on the left is wrong rest all is alright

Answer 16

ok.. so what would be in place of "v" in the equation?

Answer 17

just put it as \(v\)
we don't know any numerical value of v so we just put it as \(v\)

so our equation becomes this- \(v=0+3(6)\)
agree?

Answer 18

yes