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Physics 15 Online
OpenStudy (isuckatschool43):

Physics help please

OpenStudy (isuckatschool43):

@Astrophysics

OpenStudy (isuckatschool43):

Which best explains why elements with a completely full outer shell of electrons do not usually bond with other elements to form compounds? A. A full outer shell of electrons indicates a stable state, making the formation of compounds unnecessary. The full outer shell was obtained by releasing electrons instead of forming a compound. B. These elements have obtained electrons from other elements without bonding to create a full outer shell of electrons, and a stable state. C. Elements with a completely full outer shell of electrons are in their most stable state. Therefore, achieving stability through the formation of compounds is not necessary. D. Because electrons orbit some atoms in three dimensional space, they move to different orbitals to stabilize the atom, making the formation of compounds unnecessary. I got A

OpenStudy (isuckatschool43):

@Michele_Laino

OpenStudy (isuckatschool43):

am i right?

OpenStudy (michele_laino):

I think that the stability also can be obtained by gaining electrons

OpenStudy (isuckatschool43):

so its B?

OpenStudy (michele_laino):

no, I think that option B is a wrong option, please consider this example: |dw:1451436601245:dw| here the atom of oxygen and the two atoms of chlorine, share some electrons, so all of them can reach the stable state like a noble gas

OpenStudy (isuckatschool43):

okay

OpenStudy (michele_laino):

so, what is the right option?

OpenStudy (isuckatschool43):

D?

OpenStudy (michele_laino):

I think it is option C

OpenStudy (michele_laino):

as we can see both type atoms of chlorine and oxygen don't have a completely full outer shell of electrons

OpenStudy (isuckatschool43):

oh yeah i see that

OpenStudy (michele_laino):

also, consider this example: |dw:1451437023866:dw|

OpenStudy (michele_laino):

so, both of fluorine atoms, reach the state of noble gas Ne

OpenStudy (isuckatschool43):

yeah

OpenStudy (isuckatschool43):

so C for sure

OpenStudy (isuckatschool43):

i have a couple more that i need help with, if you could

OpenStudy (isuckatschool43):

This is the equation for the formation of magnesium chloride. Mg(s) + 2HCl(l) → MgCl2(aq) + H2(g) Which are the reactants and the products in this reaction? A. The reactants are MgCl2 (magnesium chloride) and H2 (hydrogen); the products are Mg (magnesium) and HCl (hydrochloric acid). B. The reactants are Mg (magnesium) and H2 (hydrogen); the products are MgCl2 (magnesium chloride) and HCl (hydrochloric acid). C. The reactants are Mg (magnesium) and HCl (hydrochloric acid); the products are MgCl2 (magnesium chloride)and H2 (hydrogen). D. The reactants are MgCl2 (magnesium chloride) and HCl (hydrochloric acid); the products are Mg (magnesium) and H2 (hydrogen). I got C

OpenStudy (michele_laino):

that's right!

OpenStudy (isuckatschool43):

okay. maybe like 2 or 3 more if you have time :)

OpenStudy (michele_laino):

ok! :)

OpenStudy (isuckatschool43):

What number should be substituted for the question mark to balance the equation and why is that the correct number? 2C2H6 +?O2 → 4CO2 + 6H2O + heat A. The number 4 is needed to balance the equation. The right side of the equation shows 8 oxygen atoms, so the left side needs 4 × O2. B. The number 3 is needed to balance the equation. The right side shows 6 oxygen atoms, so the left side needs 3 oxygen atoms. C. The number 7 is needed to balance the equation. The right side of the equation shows 14 oxygen atoms, so the left side needs 7 × O2. D. The number 5 is needed to balance the equation. The right side shows 4 oxygen atoms in carbon dioxide and 6 oxygen atoms in water for a total of 10 oxygen atoms. I got C

OpenStudy (michele_laino):

that's right!

OpenStudy (isuckatschool43):

OpenStudy (michele_laino):

what is your answer?

OpenStudy (isuckatschool43):

C

OpenStudy (michele_laino):

that's right! speed is given by the slope of the line, so more is the slope and more is the speed

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

I think A

OpenStudy (isuckatschool43):

because the slope is the steepest

OpenStudy (michele_laino):

here we have this slope: distance/time, which is a speed not an acceleration

OpenStudy (michele_laino):

along the line CD, the object is at rest

OpenStudy (michele_laino):

since the distance doesn't change

OpenStudy (isuckatschool43):

So D

OpenStudy (michele_laino):

no, option D is a wrong option. please note that, along the line AB the speed is constant, so acceleration=0, the same occurs along the line CD, since here the object is at rest

OpenStudy (michele_laino):

so, what can you conclude?

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