What is cos θ given (–2, –5) is a point on the terminal side of θ?
www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.440963.html might help with the answer
If the coordinate is (-2,-5) that's obviously the third quadrant right? We can make a triangle and figure out the hypotenuse using pythagorean theorem. |dw:1451579919245:dw| the triangle of course is not to scale. Then you may use your trig ratios.
Make sure you're careful as it's quadrant 3
cos is -ve in III quradent.
My options are: 5/2 -5√29/29 -2√29/29 5√29/29
@Astrophysics
ok give me a sec
-2/-5?
find 3rd side and dircet find cos
@Astrophysics give you the way to find hypotenuse of the right triangle. But you have to figure out where the theta is. My pic gave you where the theta is, right? |dw:1451581789289:dw|
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