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Can someone please check my answer.
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Your question please! :) @Susanna
\[(Given) \cos \Theta =\frac{ 3 }{ 7 } (and) 0\le \Theta \le \frac{ \pi }{ 2 } \] find sin theta and tan theta.
use sin^2 x=1-cos^2x and tan x =sin x / cos x
my answer: \[\sin \theta = \frac{ \sqrt{40} }{ 7 }\]
all values are +ve since angle lie in I quadrant.
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yes correct
\[\tan \theta = \frac{ \sqrt{40} }{ 3 }\]
is that correct?
yes
thank you so much!
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welcome
|dw:1451586060062:dw|
Once you see the triangle, it's easy to find sin theta and tan theta. You are correct. Good job!
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