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if f(x)=2x+6 and g(x)=x^3, what is (g^o f)(0)
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That means you need to evaluate f(0) first then your answer you would plug into g(x)
try it, it is identical to the last one
Wouldn't it be 2(0)+6=6
yes that is step one
then take 6 for my new x
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take that and plug it into G
exactly
and then just cube it?
right
my new x would be 216
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actually yes, but that is not the "new x" that is \[g(f(0))\]
Thank you
yw
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