The graph below shows a company's profit f(x), in dollars, depending on the price of pencils x, in dollars, being sold by the company: Part B: If at one time the profit of the company was at least $100, what domain could possibly produce this profit? Part C: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent? I have attached the graph below.
For Part B, it appears that the domain would be x => 2, x<=9.7.
Is this correct? @triciaal @sleepyjess @mathmale @mathstudent55 @mathmate @zepdrix @ganeshie8 @ParthKohli @pooja195
do you have the function for the graph? what exactly is f(x)?
Where did you get 9.7?
x => looks to be correct.
*x=>2 I mean
For C, do you know the formula for average rate of change (or slope)?
@epistemeal No I don't. And for
Question B, if you look at the question is says If at one time the profit of the company was at least $100, what domain could possibly produce this profit?
It says at least 100$. I got the 9.7, because if you look at the graph
The right side of the graph starts to go down, around 9.7 is the place where it reaches 100 on the right side of the graph. I assumed they wanted to know both sides
Alright. This is something you'll need to keep. it's \[(y_2 - y_1)\div(x_2-x_1)\]. Or rise (change in y) over run (change in x)
You have the right idea, but it looks more like 8 for me.
So can you get the average rate of change now?
@epistemeal I know the Rise over Run thing, but does that apply to a line that is curved?
Oh and what should the domain be? x => 2, x<=8?
It should for *average* rate of change. And yes, that looks right. good job
Alright, Part C: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent?
So the coordinates for x = 2 and x = 5 are
(2, 100) and (5, 160)
Equation: (y2−y1)÷(x2−x1)
y2 = 160, y1 = 100 x2 = 5, x = 2 @epistemeal ?
So that would be
\[\frac{ 160 - 100 }{ 5 - 2 } = \frac{ 60 }{ 3 } = \frac{ 20 }{ }\]
@epistemeal ????????
So would the average rate of change be 20?
Oh, the last fraction is missing a 1 in the denominator
That looks perfectly correct. Nice
Yeah I got it.
So the average rate of change would be about 20, correct?
Yes
And the domain is x => 2, x<=8, correct?
Yes
Alright, Thanks again @epistemeal !
No problem!
Bye!
If you're satisfied, could you click the little "best response" button on one of my responses?
Already did. :) g2g!
oh ok. See ya!
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