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Mathematics 14 Online
OpenStudy (anonymous):

The graph below shows a company's profit f(x), in dollars, depending on the price of pencils x, in dollars, being sold by the company: Part B: If at one time the profit of the company was at least $100, what domain could possibly produce this profit? Part C: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent? I have attached the graph below.

OpenStudy (anonymous):

OpenStudy (anonymous):

For Part B, it appears that the domain would be x => 2, x<=9.7.

OpenStudy (anonymous):

Is this correct? @triciaal @sleepyjess @mathmale @mathstudent55 @mathmate @zepdrix @ganeshie8 @ParthKohli @pooja195

OpenStudy (triciaal):

do you have the function for the graph? what exactly is f(x)?

OpenStudy (anonymous):

Where did you get 9.7?

OpenStudy (anonymous):

x => looks to be correct.

OpenStudy (anonymous):

*x=>2 I mean

OpenStudy (anonymous):

For C, do you know the formula for average rate of change (or slope)?

OpenStudy (anonymous):

@epistemeal No I don't. And for

OpenStudy (anonymous):

Question B, if you look at the question is says If at one time the profit of the company was at least $100, what domain could possibly produce this profit?

OpenStudy (anonymous):

It says at least 100$. I got the 9.7, because if you look at the graph

OpenStudy (anonymous):

The right side of the graph starts to go down, around 9.7 is the place where it reaches 100 on the right side of the graph. I assumed they wanted to know both sides

OpenStudy (anonymous):

Alright. This is something you'll need to keep. it's \[(y_2 - y_1)\div(x_2-x_1)\]. Or rise (change in y) over run (change in x)

OpenStudy (anonymous):

You have the right idea, but it looks more like 8 for me.

OpenStudy (anonymous):

OpenStudy (anonymous):

So can you get the average rate of change now?

OpenStudy (anonymous):

@epistemeal I know the Rise over Run thing, but does that apply to a line that is curved?

OpenStudy (anonymous):

Oh and what should the domain be? x => 2, x<=8?

OpenStudy (anonymous):

It should for *average* rate of change. And yes, that looks right. good job

OpenStudy (anonymous):

Alright, Part C: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent?

OpenStudy (anonymous):

So the coordinates for x = 2 and x = 5 are

OpenStudy (anonymous):

(2, 100) and (5, 160)

OpenStudy (anonymous):

Equation: (y2−y1)÷(x2−x1)

OpenStudy (anonymous):

y2 = 160, y1 = 100 x2 = 5, x = 2 @epistemeal ?

OpenStudy (anonymous):

So that would be

OpenStudy (anonymous):

\[\frac{ 160 - 100 }{ 5 - 2 } = \frac{ 60 }{ 3 } = \frac{ 20 }{ }\]

OpenStudy (anonymous):

@epistemeal ????????

OpenStudy (anonymous):

So would the average rate of change be 20?

OpenStudy (anonymous):

Oh, the last fraction is missing a 1 in the denominator

OpenStudy (anonymous):

That looks perfectly correct. Nice

OpenStudy (anonymous):

Yeah I got it.

OpenStudy (anonymous):

So the average rate of change would be about 20, correct?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

And the domain is x => 2, x<=8, correct?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Alright, Thanks again @epistemeal !

OpenStudy (anonymous):

No problem!

OpenStudy (anonymous):

Bye!

OpenStudy (anonymous):

If you're satisfied, could you click the little "best response" button on one of my responses?

OpenStudy (anonymous):

Already did. :) g2g!

OpenStudy (anonymous):

oh ok. See ya!

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