3a^3-5b^3+?a^3+?b^3=(a^3+b^3
\[(3a^3-5b^3)+?a^3+?b^3=(a^3+b^3\]
I think the answer it -3a^3 5b^3
What are the coefficients on the right? :) \(\large\rm a^3=?~~~0a^3\) What is the magical number that they're hiding from us? Is it a zero?
I have to find two numbers one for a and one for b that make the equation true to equal (a^3b^3)
+
thats the answer
I'm just trying to get you to realize how many a^3 are on the right side of the equation.
yeah 0 for a and b
No no no. 0apples is just 0, I wouldn't even have to write the apples. When I write the word "apple", that implies ONE apple, yes? When I don't write a number next to it, it's an invisible 1, not an invisible 0 :)
So you have 1a^3 and 1b^3 on the right side of your equation.
okay I see now the answer you be a=-2 b=+6
was just one off
Ahh there we go! :)
This is why you are the best!
lol :p
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