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Mathematics 8 Online
OpenStudy (anonymous):

Can someone explain this please.

OpenStudy (anonymous):

Cory has 15 die-cast cars in his collection. Each year his collection increases by 20%. Roger has 40 cars in his collection. Each year he collects 1 additional car. Part C: After approximately how many years is the number of cars that Cory and Roger have the same? Justify your answer mathematically

OpenStudy (anonymous):

cory: y = 15*1.2^x roger: y = 40 + 1*x solve 15*1.2^x = 40 + 1*x

OpenStudy (boldjon):

So for part A, Roger's function is relatively easy to figure out

OpenStudy (boldjon):

So since he is constantly adding one more and he already starts with 40, we know it will be y=x+40 Where 40 is the constant (he starts with this many) x is the rate at which he adds cars (he adds one so its 1x, but thats the same as x)

OpenStudy (anonymous):

Okay, thanks!

OpenStudy (boldjon):

np

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