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Statistics 11 Online
OpenStudy (anonymous):

Use the table of random numbers below to carry out five repetitions in the simulation method you described in (A) above. Mark the table so that it's clear to the reader how you did the simulation. Begin with the first element of the first row. If it's necessary to continue on past the first row, start at the beginning of each row. Based on your five simulations, what's your best guess as to the number of trials required to achieve three successes?

OpenStudy (anonymous):

26411 94292 06340 97762 37033 85968 94165 46514 80011 09937 57195 33906 94831 10056 42211 65491 92813 87503 63494 71379 76550 45984 05481 50830

OpenStudy (boldjon):

gimme a sec

OpenStudy (anonymous):

If 0, 1, 2 is a success, and 4-9 is a failure, then Set 1 — Number of successes: 5/10 Set 2 — Number of successes: 3/10 Set 3 — Number of successes: 1/10 Set 4 — Number of successes: 2/10 Set 5 — Number of successes: 5/10 (I divided the sets into 10s) What do i do now?

OpenStudy (anonymous):

3-9 is a failure*

OpenStudy (anonymous):

"Based on your five simulations, what's your best guess as to the number of trials required to achieve three successes?" idk how to answer that

563blackghost (563blackghost):

When I first looked at this I thought of mean for some reason....you would add the whole row and then divide how many simulation there are in each row so 5.... that what I think it means ^^

563blackghost (563blackghost):

@robjoe

OpenStudy (anonymous):

thats what i was thinking too... im not sure tho. It sounds like it has a specific thing it is asking.

OpenStudy (anonymous):

maybe a ratio or percentage...

563blackghost (563blackghost):

Is this multiple choice?

OpenStudy (anonymous):

no, it is short answer

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