can someone give me a clue how to solve the attached image finding all sides and angles in both triangles?
image is attached
I know to use laws of sines and cosines...just not sure how to split the bottom side or the top two angles in the top of the two triangles
First of all, you seem to have drawn an altitude from the base to point C. Did you intend to draw an altitude? If so, do your best to show that this line is perpendicular to the base.|dw:1452105185897:dw|
Or did you intend the drawing to look as it does?|dw:1452105324840:dw|
okay...I am certain that is an altitude...
Good. That helps ... a lot!
i wish it would've helped me:)
angle A is 58 degrees, and the hypotenuse of that triangle is 29. How would you go about finding the height of the largest triangle in your diagram? I've called that the "altitude."
sin 58 = x/29 so altitude is 29 * sin58
Think: which trig function would work best here? Which other function would work? That looks good. I assume that your "x" refers to the altitude of the largest triangle. To 2 decimal places, what is the x, the altitude?
24.59
Beautiful! What would you like to determine next?
the line left of the altitude?
Here's where we run into some ambiguity. I had thought that you and I had agreed that the solid line was actually the altitude. So, it's not?
could you possibly take and share a screen shot showing the problem in question?
nope...god...I am sorry...
you misunderstood me...or I didn't clarify well...
Set me straight. Which assumptions should I make about your drawing and your goals?
the solid line is NOT AN ALTITUDE...the dotted line is the altitude...the solid line to the left is the one I need to determine...
is it possible to find it?
I see. Happy to have that clarification. At least, we do now have the altitude: 24.59.
What approaches have you considered using to determine the length of that solid line?
yes and I have angle C and side AB Measure angle C is 50.933, measure angle B is 71.067 and side AB is 23.8036
I need the 2 angles that make up angle C or just one of them...or the two segments that make up AB or just one of them...or any one of those four unknowns...would allow me to find the other three...
I must go to lunch...but be back in a few minutes...thank you for your help...
OK. If you like, msg me when you return. Can't promise I'll be immediately available, but do know I'll be on at various times today.
i am back...
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