Expand (n-4)^6
can you expand (n-4)^2, then you have 3 of those left (n-4)^6 = ((n-4)^2 )^3
lots of keeping track of powers of n
you should get to these as the coefficients for x^6 town to x^0 1 -24 240 -1280 3840 -6144 4096
Available Answers: A: \[n^6-24n^5+240n^4-1280n^3+3480n^2-6144n+4096\] B: \[n^6+24n^5+240n^4-1280n^3+3480n^2-6144n+4096\] C: \[n^6-24n^5+240n^4-1290n^3+3840n^2-6144n+4096\] D: \[n^6-24n^5+240n^4-1280^3+3480n^2-6144n+5000\]
Apologies for taking so long, it's a lot of numbers to type out.
oh.. ha you didnt have to, or take a screen shot instead maybe
if you can expand things without problem i would just use a algebra system to do it for you
Expanding things is a bit of a problem for me.
it is everything from one quantity multiplied to everything from the other quantity like for this with only 2 terms in each, take 2 of the 6 (n - 4)^2 = (n-4)*(n-4) = n^2 - 4n - 4n + 16 (n-4)^2 = n^2 - 8n + 16
gets to be not fun |dw:1452146189641:dw|
I see.
u can also use the binomial expansion :)
What is the binomial expansion?
Also I think the answer is A.
Okay.
what was the pascal triangle for again, i was thinking about that on this one
although for sure not applied
I think it's for finding answers to problems like this one.
i thought they were symmetrical for the numbers
okay so binomial expansion is like a general formula to expand \((a+b)^n\) it says that- \((a+b) ^n=~^nC_0(a)^{n-0}(b)^0+~^nC_1(a)^{n-1}(b)^1+~^nC_2(a)^{n-2}(b)^2+........+~^nC_n(a)^{n-n}(b)^n\)
Sounds good.
okay and we just gotta figure out what is our \(a\),\(b\) and \(n\) from \((n-4)^6\) and just substitute it in the equation :)
I think that A would be N, B would be -4 and N would be exponent six?
yes n will be 6 now just put those values in the equation and try to simplify it
That was long. I ended up with the string of numbers associated with the first answer.
how can you know if you can take some ugly thing and go back the other way to a simple higher power single binomial?
If you can get there in the first place?
you can take binomial expansion method when you already don't know the expansion formula :) like here i didn't knew what is the formula to (a+b)6 so i used binomial expansion
Okay. I'll use that.
Thanks for the help, by the way.
np :)
Well, after I wrote it down, and tried it out again, I ended up with \[n^6-24n^5+240n^4-1280^3+3840n^2-6144n+4096\]
if they gave you a string of powers like that, maybe any number of em, is it possible to prove you can put that into some simpler polynomial thing
or prove you cant, either case
Let me see.
like a 10^(42) term polynomial, can that be factored into some simpler form
I don't think so.
well if it follows this binomial coefficients , it can but, ah nvm, just thinking
I'll definitely need to work on this subject.
I'll just close the problem, if it's alright with you. Thank you for all your help! :)
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