Question

I have a question about similare shapes. The question gives me two triangles and the information of the triangles as follows:
Triangle A: Base length of 20cm
Area of 187.5cm^2
Triangle B: Base length of 30cm
The question asks me to find the area of triangle B. I will post what I tried to do as a comment :)

Answer 1

What I tried:
\[\frac{ 30^{2} }{ 20^{2} }= \frac{ x }{ 187.5 }\]

\[\frac{ 900 }{ 400 } x 187.5= 421.875\]

Answer 2

That last equation should be a multiplication sign not an x (oops sorry)

Answer 3

You don't need to square 20 & 30. The first thing you should do is find the height of the first triangle using the area formula A=1/2 *base*height
187.5=1/2*20*x
x=18.75
Now, you'd use proportions
20/18.75=30/x
Solve for x

Answer 4

I get 32?

Answer 5

x=28.124991

Answer 6

In my text book the answer is supposed to be 125cm^2

Answer 7

I can post a picture of the question if that would help? Its possible I didnt explain things very well

Answer 8

Yes please

Answer 9

Ok, coming up

Answer 10

It is question a)

Answer 11

This is an example given and how i tried to solve it

Answer 12

You explained it right. We still get x=28.125 though, which would make the are of triangle B 421.875cm^2
Sorry we couldn't help.

Answer 13

Thats ok, thank you for trying :)