Question

help

Answer 1

@DanJS

Answer 2

@study

Answer 3

@studygurl14

Answer 4

I can try to help.

Answer 5

if u r in 9th+ u know

Answer 6

I am in the 7th grade..

Answer 7

ok then u cant

Answer 8

Okay, sorry though, I didn't know.

Answer 9

danny boy hey so 48s+54 factor

Answer 10

mail it too me

Answer 11

dan???

Answer 12

@SolomonZelman

Answer 13

sort of like multiplying by 1, looking to take the common pieces from each term there, only the constants appear in both terms, the greatest number you can pull out of each one...6

similar to multiplying by 1 or 6/6

\[\large \frac{ 6 }{ 6 }*(48s + 54) = 6*(\frac{ 48s }{ 6 }+\frac{ 54 }{ 6 })\]

Answer 14

so thats the answer??

Answer 15

yeah , simplify the fractions, 6(8s + 9),
no more common pieces in the quantity terms

distributing that answer should take you back to the original thing

Answer 16

for constant values in all the terms, factor the gcf, for the variable terms common to all, take the highest power out that all terms contain

Answer 17

its incorrect

Answer 18

factoring like here is just seeing what numbers and variables all the terms contain, and writing that once in front, and then reduce each term by that amount to simplify

48s + 54 = 6*(8s + 9)

Answer 19

maybe typed something different than they want, computer graded?

Answer 20

yup i typed something wrong lol

Answer 21

for variables, for example something like

x^2*y + x*y^2

both terms have a common x and y, the lowest common power, so it goes to

(x*y)*(x + y)

Answer 22

im still confused to what the question is